print( ["even", "odd"][num % 2] )If you need to avoid evaluating the wrong branch:
print( [lambda: "even", lambda: "odd"][num % 2]() )Cursed
Not as cursed as
print("eovdedn"[n%2::2])
print("odd" if num % 2 else "even")That’s the native python version, for those curious
The ternary syntax is really my only real gripe with python design – putting the conditional BETWEEN the true and false values feels so very messy to me.
At least you guys have ternary syntax cries in kotlin.
in Scala, everything is an expression, including “if”, maybe kotlin is the same?
Eh, reads pretty naturally to me. That said,
(like I lisp)Lisps makes more sense to me though
(if condition a b)
VS
a if condition else b
Why is the return first?
For optimal performance, you should rewrite it in Rust:
inline_python::python! { print(js2py.eval_js("(number) => number % 2 ? 'odd' : 'even'")(number)) };And now you can use wasm to run it in a browser!
Please. That’s C’s ternary operator. JS is just a pile of garbage cosplaying as a programming language
Why do you say it’s a pile of garbage?
Because of all the garbage
Clearly the garbage collector is too effective
No they’re not supposed to be piling it up
num % 2isn’t a boolean result in any of these languages, so I feel like it would always output “odd”Edit: 0 is false, everything else is true.
0 is false in C, Python, and JS. It should work
